Modelling in Mechanics: Summary Sheet

Mechanics Year 1, Chapter 8: models, assumptions, quantities, units and vectors on two A4 sides, to print as notes or with the key words left blank.

Version
Two A4 sides. The fill-in-the-blanks versions print a third page with the answers.

Modelling in Mechanics Mechanics Year 1 ¡ Chapter 8 ¡ Side 1 of 2

Mathematical models

A mathematical model is a simplified description of a real situation, used to make predictions.

A modelling assumption simplifies the situation so that the mathematics can be done (for example, ignoring air resistance). A model is improved, or refined, by changing its assumptions.

Exam tip: state an assumption in context and say what it means: “the string is light, so the tension is the same throughout”.
Real-world problem Make assumptions;set up the model Solve the mathematics Compare the predictionswith real data Not close enough?Refine the assumptions Close enough: use it

Modelling assumptions

WordWhat it meansWhat it means for the working
ParticleIts dimensions are negligible, so its mass acts at a single point.Ignore rotation (spin) and air resistance; all the forces act at one point.
RodLong, thin and rigid: every dimension except its length is negligible.It does not bend; its mass is along a line.
LaminaA flat object whose thickness is negligible.Its mass is spread over a flat area.
UniformIts mass is spread evenly (non-uniform: not evenly).Its weight acts at its geometrical centre (a rod: its midpoint).
LightIts mass is negligible (a string, a rod, a pulley).Its weight is ignored; the tension is the same throughout a light string.
InextensibleIt does not stretch.Particles joined by it have the same magnitude of acceleration.
Smooth surfaceThere is no friction.The only force from the surface is the normal reaction.
Rough surfaceObjects in contact with it experience friction.Friction acts along the surface, opposing the motion.
Smooth pulleyNo friction between the pulley and the string.The tension is the same on both sides of the pulley.
BeadA particle with a hole in it, threaded on a wire (a rigid, thin length of metal) or a string.It moves along the wire (no friction if the wire is smooth).
PegA fixed support from which a body can hang or on which it can rest.It has no dimensions; it can be rough or smooth.
Air resistance negligibleThe resistance of the air is ignored.The only force on a falling object is its weight, so its acceleration is $g$.
GravityThe acceleration due to gravity is constant.$g = 9.8\text{ m s}^{-2}$ (a question may say $10\text{ m s}^{-2}$).
EquilibriumThe resultant force is zero.At rest, or moving with constant velocity.

Using a model

  • Substitute into the model: e.g. the diver $h = 10 + 4t - 4.9t^2$: when $t = 1$, $h = 9.1$ m.
  • Interpret each number: put $t = 0$; here $10$ is the height of the board (m) and $4$ is the speed (m s⁝š) she leaves it with, upwards.
  • Solve: she reaches the water when $h = 0$; reject the negative solution of the quadratic.
  • Greatest value of a quadratic: on its line of symmetry (or complete the square).
  • A model is only valid for a range of values, e.g. $0 \le t \le 1.89$, until something changes (it lands, stops or enters the water). A negative height, or a car “moving backwards”, shows it is no longer valid.

Quantities, Units and Vectors Mechanics Year 1 ¡ Chapter 8 ¡ Side 2 of 2

SI units

QuantitySI unit
masskilogram (kg) ¡ base unit
length, displacementmetre (m) ¡ base unit
timesecond (s) ¡ base unit
speed, velocity$\text{m s}^{-1}$
acceleration$\text{m s}^{-2}$
force, weightnewton (N), $1\text{ N} = 1\text{ kg m s}^{-2}$

One newton is the force that gives a mass of $1$ kg an acceleration of $1\text{ m s}^{-2}$.

Weight is the force due to gravity: $W = mg$. A mass of $5$ kg has weight $5 \times 9.8 = 49$ N. Mass is in kg; weight is in N.

Converting to SI units: $72\text{ km h}^{-1} = \frac{72 \times 1000}{3600}\text{ m s}^{-1} = 20\text{ m s}^{-1}$ (divide by $3.6$); $450\text{ g} = 0.45\text{ kg}$; $2.5$ minutes $= 150\text{ s}$.

Scalars and vectors

A scalar has magnitude (size) only. A vector has magnitude and direction.

ScalarVector
distancedisplacement
speedvelocity
massweight (it always acts downwards, but that is still a direction)
timeacceleration, force

Speed is the magnitude of velocity; distance is the magnitude of displacement.

Signs in a straight line: choose a positive direction. A velocity of $-3\text{ m s}^{-1}$ means moving the other way at $3\text{ m s}^{-1}$. When the velocity and the acceleration have opposite signs, the object is slowing down (a “deceleration”).

Vectors in $\mathbf{i}$, $\mathbf{j}$ form

$\mathbf{i}$ and $\mathbf{j}$ are unit vectors (magnitude $1$) in the directions of the $x$ and $y$ axes, perpendicular to each other.

Magnitude of $p\mathbf{i} + q\mathbf{j}$: $\sqrt{p^2 + q^2}$ by Pythagoras’ theorem. For a velocity this is the speed: $(3\mathbf{i} - 4\mathbf{j})\text{ m s}^{-1}$ has speed $\sqrt{3^2 + (-4)^2} = 5\text{ m s}^{-1}$.

Resultant force: add the forces, e.g. $(2\mathbf{i} + 5\mathbf{j}) + (4\mathbf{i} - 3\mathbf{j}) = (6\mathbf{i} + 2\mathbf{j})$ N.

Constant velocity: displacement $=$ velocity $\times$ time; position $\mathbf{r} = \mathbf{r}_0 + \mathbf{v}t$.

From speed and direction: speed $v$ at $\theta$ above $\mathbf{i}$ gives $v\cos\theta\,\mathbf{i} + v\sin\theta\,\mathbf{j}$; put in the signs for the quadrant.

The angle with $\mathbf{i}$, $\mathbf{j}$, $-\mathbf{i}$ or $-\mathbf{j}$: always draw a diagram. “The angle with $\mathbf{i}$” means with the positive $\mathbf{i}$ direction, and the answer is between $0^\circ$ and $180^\circ$.

i −i −3i + 4j α θ

$\alpha = \tan^{-1}\left(\dfrac{4}{3}\right) = 53.1^\circ$, the angle with $-\mathbf{i}$.
The angle with $\mathbf{i}$ is $\theta = 180^\circ - 53.1^\circ = 126.9^\circ$.
With $\mathbf{j}$ or $-\mathbf{j}$, use $\tan^{-1}\left(\dfrac{|p|}{|q|}\right)$ in the same way.

Improving a model

  • Compare the predictions with real data. Is the answer reasonable?
  • Find the assumption that causes the difference, and change it:
    • include air resistance (a ball goes less high, a skydiver reaches a steady speed);
    • model a surface as rough, not smooth (include friction);
    • model an object as a rigid body, not a particle (spin, turning);
    • model a rod as non-uniform, or a string as extensible.
  • Say how the change moves the prediction (higher, lower, longer…).
  • A refined model is more realistic; the mathematics is usually harder.

Modelling in Mechanics: answers to the blanks Mechanics Year 1 ¡ Chapter 8